Hello :
tan²(θ) = 3.. equi : tan(θ) = √3 or tan(θ) = -√3
1 ) tan(θ) = √3
tan(θ) = tan(<span>π/3)
</span>θ = π/3 +kπ k in Z
2)tan(θ) = -√3
tan(θ) = tan(-π/3)
θ = -π/3 +kπ k in Z
9514 1404 393
Answer:
D
Step-by-step explanation:
Solve x = f(y) for y.
x = ∛(y/9) -4
x +4 = ∛(y/9) . . . . . add 4
(x +4)³ = y/9 .. . . . . cube
9(x +4)³ = y . . . . . . multiply by 9
The inverse function is ...
f⁻¹(x) = 9(x +4)³ . . . . . matches the last choice
16/25 is 0.64 as a fraction in lowest terms
Answer:
There should be one more equation
Step-by-step explanation: