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emmainna [20.7K]
3 years ago
8

Suppose the variable x is represented by a standard normal distribution. What is the probability of x > 0.3 ? Please specify

your answer in decimal terms and round your answer to the nearest hundredth (e.g., enter 12 percent as 0.12).
Mathematics
1 answer:
uysha [10]3 years ago
5 0

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

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Answer:

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Step-by-step explanation:

Rotation around center (x₀ , y₀), counterclockwise rotation θ degree

x₂ = (x₁-x₀)cosθ - (y₁-y₀)sinθ + x₀  

y₂ = (x₁-x₀)sinθ + (y₁-y₀)cosθ + y₀

A(-2.4) -> counterclockwise rotation 90°

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3 years ago
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Answer:

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Step-by-step explanation:

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