Answer:
Te answer is: The demand for new cars will rise, so the demand for auto loans will also rise, increasing the labor demand in companies that offer auto loans.
Explanation:
When the price of a good or service decreases, the quantity demanded for that good or service will increase.
Interest rates can be considered as the price of a loan, so when interest rates fall, the quantity demanded for loans will increase. This factor plus an increase in car sales, low gasoline prices and low unemployment are the perfect conditions for the auto loan industry to flourish.
When any industry is expected to do so well, their demand for labor is also expected to increase.
Answer:
Management, Operations, Marketing, Accounting, Finance
Explanation:
-Management: planning and knowing your business resources to achieve it's goals
-Operations: The transformation of resources into goods/products, making sure the goods are high quality
-Marketing: Identifies customer's needs, develop and decide the price and quality of products
-Accounting: financial and managerial information. Accountants work to communicate finance information to managers
-Finance: Obtaining and managing a companies funds. Who gets/needs money, and how much do they get
Answer:
$259.34
Explanation:
the value of the stock can be determined using the two stage dividend discount model.
In the first stage, the present value would be determined using a discount rate of 18%.
In the second stage, the present value would be determined using a discount rate of 6%.
Values from the first and second stage would be added together to determine the value of the stock
First stage
Present value in year 1 = ($3.2 x 1.18) / 1.087 = $3.47
Present value in year 2 = ($3.2 x 1.18²) / 1.087² = $3.77
Present value in year 3 = ($3.2 x 1.18³) / 1.087³ = $4.09
Present value in year 4 = ($3.2 x 1.18^4) / 1.087^4 = $4.44
Second stage
($3.2 x 1.18^4 x 1.06) / (0.087 - 0.06) = 243.57
Value of the stock = $3.47 + $3.77 + $4.09 + $4.44 + 243.57 = $259.34
Answer:
Price of bond = $ 924.50
Explanation:
<em>The value of the bond is the present value(PV) of the future cash receipts expected from the bond. The value is equal to present values of interest payment plus the redemption value (RV). </em>
Value of Bond = PV of interest + PV of RV
The price of the bond can be worked out as follows:
Step 1
PV of interest payments
annul interest payment = 6.4 % × 1,000 = 64
Annual yield = 7.5%
Total period to maturity (in years) =10
PV of interest =
64 × (1- (1.075)^(-10)/)/0.075= 439.30
Step 2
PV of Redemption Value
= 1,000× (1.075)^(-10) =
485.19
Step 3
Price of bond
439.30 + 485.19 =$924.49
Price of bond = $ 924.50
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
