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devlian [24]
4 years ago
14

8. Write an equation for the line that is parallel to the given line and that passes through the given point.

Mathematics
2 answers:
neonofarm [45]4 years ago
4 0

Answer:

y = 3x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 8 ← is in slope- intercept form

with slope m = 3

• Parallel lines have equal slopes, hence

y = 3x + c ← is the partial equation of the parallel line

To find c substitute (- 6, - 17 ) into the partial equation

- 17 = - 18 + c ⇒ c = - 17 + 18 = 1

y = 3x + 1 ← equation in slope- intercept form

hichkok12 [17]4 years ago
3 0

Answer:

y = 3x + 1

Step-by-step explanation:

an equation for the line that is parallel to the given line and that passes through the given point.

y = 3x - 8; (-6, -17) turn it into a equation The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 8 ← is in slope- intercept form

with slope m = 3

To find c substitute (- 6, - 17 ) into the partial equation

- 17 = - 18 + c ⇒ c = - 17 + 18 = 1

y = 3x + 1 ← equation in slope- intercept form

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The correct answer would be C. rectangle!

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Every year a hall of fame inducts legendary people to the hall. The table shows the number of inductees for each year. What are
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Answer:

Domain : [2000, 2004]

Step-by-step explanation:

From the given set of data,

Years given are the independent variable plotted of x-axis.

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Therefore, domain of the given graph will be the set of x-values (mentioned as years).

Domain : [2000, 2004]

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Read 2 more answers
2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

  • i.e S(a) = S(b)

75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

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2 years ago
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11 is the length

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