Between two square roots of integers, you can find pi are square roots
<h3>Between which two square roots of integers can you find pi?</h3>
In mathematics, the square root of a number x is a number y such that y2 = x. Another way to put this is to say that a square root of x is a number y whose square equals x.
The number that, when multiplied by itself, results in the value that is sought is referred to as the number's square root.
Since 3 < pi < 4,
√9 < pi √16
In conclusion, what this demonstrates is that the value of pi may be found anywhere between the square roots of -9 and -10.
Read more about square roots
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Answer:
268.08
Step-by-step explanation:
first you take your radius and put it in the equation V=4/3πr³ when you insert the 4 you calculate it to get 268.08257
Answer:
x = - 1, x = 
Step-by-step explanation:
Given
8x² + 7x - 1 = 0 ← in standard form
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 8 × - 1 = - 8 and sum = + 7
The factors are + 8 and - 1
Use these factors to split the x- term
8x² + 8x - x - 1 = 0 ( factor the first/second and third/fourth terms )
8x(x + 1) - 1(x + 1) = 0 ← factor out (x + 1) from each term
(x + 1)(8x - 1) = 0
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
8x - 1 = 0 ⇒ 8x = 1 ⇒ x =
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes, a rectangle.
We know that the area of a rectangular shape is
Area =length x width
Since we don't have any specific data regarding Nathan's plot of land
Let's assume some figure for better understanding
Say the length is 18m
And the width is 12m
Area = 18*12
Area= 216m²
