Answer:
a) The expected number of goals team A will score is 5.1
b) The probability that team A will score a total of 5 goals is 0.1147
Step-by-step explanation:
Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also
a)
E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1
b) In order for X to be equal to 5 we have 5 possibilities
- X1 is 0 and X2 is 5
- X1 is 1 and X2 is 4
- X1 is 2 and X2 is 3
- X1 is 3 and X2 is 2
- X1 is 4 and X2 is 1
- X1 is 5 and X2 is 0
Let T1 be a poisson distribution with mean λ = 2, then






Lets do the same with a Poisson distribution T2 with mean λ = 3


Now, we are ready to compute the probability that X is equal to 5.


We can conclude that
P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147
The probability that team A will score a total of 5 goals is 0.1147
Answer:
-1
Step-by-step explanation:
∫x^2 -x +1 dx = x^3/3 -x^2/2 +x evaluated at 1 subtracting the value at 0
1/3 -1/2 +1 - (0/3 -0/2 +0)
5/6
Now lets find
∫x^2 -x +1 dx=x^3/3 -x^2/2 +x evaluated at 2 subtracting the value at 1
2^3/ 3 -2^2/2 +2 - (1/3 -1/2 +1 )
8/3 -2 +2 - (5/6)
8/3 -5/6
11/6
The total is 5/6 - 11/6 = -6/6 or -1
Answer:
Option D
Step-by-step explanation:
I solved in the picture
Hope this helps ^-^
Answer:
he can paint 8 chairs
Step-by-step explanation:
he has 78/10 liters of paint he uses 6/10 which makes it 72/10 and each chair needs 9/10 paint 9 times 8=72