Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
I might be wrong but I think it is 50 .
I know its not division,addition,multiplication,with the process of elimination its reflexive
Answer:
B
Step-by-step explanation:
The answer is B because if you move two times to the right it gives you 0.09 like the eqution.
But scientific notation requires number without decimal, so the answer cannot be E because 0.9 is a decimal.
Just reminder: B and D have the same result!! just different coefficient
Answer:
p-value: 1.000
There is enough evidence at the 1% level of significance to suggest that the proportions are not equal.
Step-by-step explanation:
We will be conducting a difference of 2 proportions hypothesis test
The hypothesis for this test is:
H0: p1 - p2=0
Ha: p1 - p2 ≠0
(p1 ) = 252/300 = 0.84
(p2) = 195/300 = 0.65
This is a 2 tailed test with a significance level of 1%. So our critical values are: z > 2.575 and z < -2.575
See the attached photo for the calculations for this test
