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2 years ago

the width of a rectangular yard is 3 yards more than twice its length. the perimeter of the garden is 192 yards

Mathematics

1 answer:

Bas_tet [7]2 years ago

6 0

Answer:

Step-by-step explanation:

W = 2L + 3, and:

P = 2W + 2L = 192

Substituting 2L + 3 for W, we get:

P = 2(2L + 3) + 2L = 192, or

4L + 6 + 2L = 192, or:

6L = 186

L = 186/6 = 31

The length is 31, the width is 62 + 3, or 65

Therefore, the perimeter P is P = 2(31) + 2(65) = 130 + 62 = 192 (OK!)

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(Refer to the attached image)

RSB [31]

Answer:

missing side: 133 cm

Explanation:

Provided 2 length sides and one angle also need to find one missing side.

So, use cosine rule:

⇒ a² = b² + c² - 2bc cos(A)

Insert values

⇒ g² = 166² + 147² - 2(166)(147) cos(50)

⇒ g² = 17794.3935

⇒ g = √17794.3935

⇒ g = 133.3956

⇒ g = 133 (rounded to nearest whole number)

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1 year ago

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3 years ago

Is this correct ? Or would the angle be considered an acute angle

tino4ka555 [31]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

The sum of two polynomials is â€"yz2 â€" 3z2 â€" 4y 4. If one of the polynomials is y â€" 4yz2 â€" 3, what is the other polynomi

gtnhenbr [62]

The sum of polynomials involves adding the polynomials

The other polynomial is $y^3 -y^2+ 4y - 1$

The sum of the polynomials is given as:

$Sum = y^3 + 3y^2 + 4y - 4$

One of the polynomials is given as:

$P = 4y^2 - 3$

Represent the other polynomial with Q.

So, we have:

$P +Q =Sum$

Substitute the expressions for P and Sum

$4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4$

Make Q the subject

$Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3$

Evaluate like terms

$Q =y^3 -y^2+ 4y - 1$

Hence, the other polynomial is $y^3 -y^2+ 4y - 1$

Read more about polynomials at:

brainly.com/question/1487158

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2 years ago

what is the slope-intercept form for a line that has a slope of -4/5 and passes through points (0,7)?

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