Solve the system using the substitution method 4x+6y=8 3x+y=9
1 answer:
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Answer:
The probability that the parcel was shipped expressed and arrived the next day = 0.2375 .
Step-by-step explanation:
We are given that a certain delivery service offers both express and standard delivery.
Let Proportion of parcels sent by standard delivery, P() = 0.75
Proportion of parcels sent by express delivery, P() = 0.25
Let <em>event B = Parcel arriving the next day</em>
Also, Probability of parcel arriving the next day given it was sent through standard delivery, P(B/) = 0.8
Probability of parcel arriving the next day given it was sent through express delivery, P(B/) = 0.95
Now, Probability that the parcel was shipped expressed and arrived the next day = P() * P(B/
) = 0.25 * 0.95 = 0.2375 .
Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is: (∵V=lbh)
The maximum combined length and girth is 144.
Therefore,
Substitute the value of y in volume of the box.
Substitute V'(x)=0.
Now apply second derivative test.
(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then
Substituting value of x = 24 and y = 48 gives 27648.
Hence, the volume in such a package is 27648 in³