Answer:
Mean = 18.625
Median = 18.5
Step-by-step explanation:
Given the following :
Age = 19, 27, 19, 18, 18, 18, 47, 19, 20, 18
The mean Age :
Mean = Σ(x) ÷ N
N = number of data
(19 + 27 + 19 + 18 + 18 + 18 + 47 + 19 +20 + 18) / 10
Σ(x) / N = 223/10 = 22.3
Rearranging to get the median:
18,18,18,18,19,19,19,20,27,47
Middle value = median ( 19 + 19)/2 = 19
The outliers in the data are:
18,18,18,18,19,19,19,20,27,47
OUTLIERS ARE VALUES
< Q1 - (1.5 × IQR)
> Q3 + (1.5 × IQR)
IQR = Q3 - Q1 (Interquartile range)
Q3 = upper quartile
Q1 = lower quartile
From the data :
Q3 = 20, Q1 = 18
IQR = Q3 - Q1 = 20 - 18 = 2
< 18 - (1.5 × 2) ; <15
> 20 + (1.5 × 2) ; >23
VAlues greater than 23 and less than 15 are outliers in the data
27 and 47
After removing outliers
N = 10 - 2 = 8
Σ(x) = 223 - (47+27) = 149
Mean = 149/8 = 18.625
X = 18,18,18,18,19,19,19,20
Median = (18 + 19)/2 = 18.5
