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4 years ago

Integers contain the whole numbers. true or false

Mathematics

2 answers:

Ostrovityanka [42]4 years ago

4 0

True...integers are whole number...both negative and positive

IRISSAK [1]4 years ago

3 0

Answer:

True

Step-by-step explanation:

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If f(x) = 3x + 2 and g(x) = x2 – x, find each value. 17 f(-2)= f(-2) =

Fynjy0 [20]

<h3>Answer: -4</h3>

Work Shown:

f(x) = 3x + 2

f(-2) = 3(-2) + 2 ... each x replaced with -2

f(-2) = -6 + 2

f(-2) = -4

4 0

3 years ago

How many times does the 8 fit into the 49

Vlada [557]

Answer:

6.125

Step-by-step explanation:

49 divided by 8

49÷8=6.125

4 0

3 years ago

Read 2 more answers

What is the solution to the inequality below? w+4≤ -1

maxonik [38]

Answer:

w≤ -5

Step-by-step explanation:

hello :

w+4≤ -1

w+4-4≤ -1-7

w≤ -5

3 0

3 years ago

Help me! ELENA HAS 6 YARDS OF RIBBON IT TAKES 1/4 YARD OF RIBBON TO MAKE A BOW HOW MANY BOWS CAN SHE MAKE WITH THE RIBBON THAT S

astraxan [27]

Answer:

24 bows

Step-by-step explanation:

5 0

3 years ago

Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2

tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

1. 2x^2 - 7x + 3

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

a = 2
b = -7
c = 3

we can use the quadratic formula: $x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}$

Substitute the a, b, and c values into the quadratic formula: $x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}$

Now simplify using the laws of pemdas: $x=\frac{7\pm\sqrt{(49)-(24)} }{4}$

Simplify even further: $x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}$

Now split this equation into two equations to solve for x: $x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}$

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

$\boxed {x=3,\frac{1}{2} }$

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

x - 3 = 0
2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

2. 3x^2 + 7x + 2

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

3x + 1 = 0
x + 2 = 0

Solve.

First factor: 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

Second factor: x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

$\boxed {x = -\frac{1}{3} , -2}$

7 0

3 years ago