Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
Answer:
x=1/3 or x=−2
if i can be brainliest that would be great
Step-by-step explanation:
Step 1: Add 2 to both sides.
3x^2+5x−2+2=0+2
3x^2+5x=2
Step 2: Since the coefficient of 3x^2 is 3, divide both sides by 3.
3x^2+5x/3=2/3
x^2+5/3x=2/3
Step 3: The coefficient of 5/3x is 5/3. Let b=5/3.
Then we need to add (b/2)^2=25/36 to both sides to complete the square.
Add 25/36 to both sides.
x^2+5/3x+25/36=2/3+25/36
x^2+5/3x+25/36=49/36
Step 4: Factor left side.
(x+5/6)^2=49/36
Step 5: Take square root.
x+5/6=±√49/36
Step 6: Add (-5)/6 to both sides.
x+5/6+ −5/6=
−5/6±√49/36x=−5/6±√49/36x=
1/3 or x=−2
Given:
The two expressions are


To find:
Whether the given expression are equivalent or non-equivalent.
Solution:
If two expressions are looking different but they are equal after simplification, then they are called equivalent expressions.
The first expression is

The first expression is equal to the second expression after the simplification.
Therefore, the given expressions are equivalent.
D=dante's cards number
a=anna's cards number
d=60
this (d) is at least (smallest is, aka greater than or equal to or <u>></u>) 6 more than (+6) 3 times as many as anna (3 times a or 3a)
d<u>></u>6+3a
d=60
60<u>></u>6+3a
subtract 6 from both sides
54<u>></u>3a
divide both sides by 3
18<u>></u>a
anna has at least 18 cards
Answer:
Given : ∠ABC is a right angle, ∠D BC is a straight angle.
To prove :∠AB D is a right angle.
Proof: ∠ ABC = 90°[ Given]
∠ D BC= 180° [ D BC is a straight line]
now, ∠ AB D and ∠ AB C are adjacent angles forming linear pair.
∠ AB D +∠ AB C =180° [By linear pair axiom]
⇒∠ AB D + 90= 180°
⇒∠ AB D=180°-90°
⇒∠ AB D=90°
∠AB D is a right angle
Hence proved.