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3 years ago

12

WHATS THE AREA OF THE TRAPIZOID?!

1 answer:

Helen [10]3 years ago

3 0

Answer: 45.. i think.

Step-by-step explanation: I couldn't really get the measurements from this photo so here is what I got. I used the formula A=a+b over 2 times h. I used 7=a, b=11,h=5. I added 7 and 11 to get 18, then divide that by 2, which equals 9. Then 9 times 5 = 45. I hope this somewhat helps.

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3 years ago

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Read 2 more answers

Calculate the sample standard deviation of data from Question 1<br> 76,45,64,80,92

mash [69]

Answer:

$S.D = 15.98$

Step-by-step explanation:

Given: 76,45,64,80,92

Required: Determine the standard deviation

We start by calculating the mean

$Mean = \frac {\sum x}{n}$

Where x-> 76,45,64,80,92 and n = 5

$Mean = \frac {76+45+64+80+92}{5}$

$Mean = \frac{357}{5}$

$Mean = 71.4$

Subtract Mean (71.4) from each of the given data

$76 - 71.4 = 4.6\\45 - 71.4 = -26.5\\64 - 71.4 = -7.4\\80 - 71.4 = 8.6\\92 - 71.4 = 20.6$

Determine the absolute value of the above result

$|4.6| = 4.6\\|-26.5| = 26.5\\|-7.4| = 7.4\\|8.6| = 8.6\\|20.6| = 20.6$

Square Individual Result

$4.6^2 = 21.16 \\26.5^2 = 702.25\\7.4^2 = 54.76\\8.6^2 = 73.96\\20.6^2 = 424.36$

Calculate the mean of the above result to give the variance

$Mean = \frac {\sum x}{n}$

$Mean = \frac{21.16 + 702.25 + 54.76 + 73.96 + 424.36}{5}\\Mean = \frac{1276.49}{5}\\Mean = 255.298$

Hence, Variance = 255.298

Standard Deviation is calculated by $\sqrt{Var}$

$SD = \sqrt{255.298}$

$S.D = 15.9780474402$

$S.D = 15.98 (Approximated)$

6 0

3 years ago

I need help klcan you draw it , thanks

NARA [144]

Answer:

Step-by-step explanation:

I think it may look like this?

8 0

2 years ago