Answer:
To obtain equivalent amount from both foods we can eat 10 ounces of Food I and 5 Ounces of food II
To obtain minimum cholesterol, the individual should eat only 21 ounces of food II and zero ounce of food for the daily supplement of the individual
Step-by-step explanation:
Food I contains 32×C + 10×E per ounce
Food II contains 20×C + 14×E
Here we have X × (Food I) + Y × (Food II) = 420 C + 170 E
32·X + 20·Y = 420 C
10·X + 14·Y = 170 E
Therefore
X = 10 and Y = 5
To minimize the cholesterol, we can increase amount of Food II to get
21 ounces of food II gives
420 units of vitamin E and 294 units of vitamin E with 273 units of cholesterol.
Answer:

Step-by-step explanation:
Given



See attachment for complete question
Required

The question requires that we calculate the theoretical probability of landing on the head.
This means that, we have to ignore the given data, and we use the following
--- sample space
--- sample size
--- occurrence of Head
So, the theoretical probability is:



Answer:
first one : (7+12+3+4+4+8)*2=76
Answer:
Step-by-step explanation:
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) = 
P(B) = 
P(AUB) = 0.68 =

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
=P(A'UB') = P(AB)'
=