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skelet666 [1.2K]
4 years ago
12

A certain library charges a flat fee of $5 for any overdue book for the first x days the book is overdue, and an additional fee

of m dollars per day for every day after x that the book is overdue. What is the fee for a book that is 12 days overdue?
Mathematics
1 answer:
bearhunter [10]4 years ago
6 0

Answer: 5 (x > 12) or 5 + m(12 - x) (x < 12)

Step-by-step explanation:

flat fee $5 for first x days +

m dolars per day after x days

So, if x > 12, for 12 days the fee is $5 because it is a flat fee that do not depend of the numbers of day.

But, we do not know how many days x is, so

if x < 12, a person will pay, for 12 days, the m times the difference of the days passed x:

5 + m(12-x)

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(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

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