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atroni [7]
3 years ago
9

Using the right triangle below. What is the name for side AC ?

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0

Answer:

B) Adjacent

Step-by-step explanation:

The hypotenuse will ALWAYS be designated as the longest side in a right triangle.

Pretend that the angle (the one with the round line) is an eyeball that is looking outwards. The eye is looking out at side BC. That means that line BC is opposite of the angle.

This leaves one side left: the adjacent side. The adjacent side is the side next to the angle. But it is the side that is NOT the hypotenuse.

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What are the solutions of this system of equations?
SpyIntel [72]

Answer:

Option C is correct.

Step-by-step explanation:

y = x^2-x-3     eq(1)

y = -3x + 5      eq(2)

We can solve by substituting the value of y in eq(2) in the eq(1)

-3x+5 = x^2-x-3

x^2-x+3x-3-5=0

x^2+2x-8=0

Now factorizing the above equation

x^2+4x-2x-8=0

x(x+4)-2(x+4)=0

(x-2)(x+4)=0

(x-2)=0 and (x+4)=0

x=2 and x=-4

Now finding the value of y by placing value of x in the above eq(2)

put x =2

y = -3x + 5

y = -3(2) + 5

y = -6+5

y = -1

Now, put x = -4

y = -3x + 5

y = -3(-4) + 5

y = 12+5

y =17

so, when x=2, y =-1 and x=-4 y=17

(2,-1) and (-4,17) is the solution.

So, Option C is correct.

7 0
3 years ago
Read 2 more answers
Is the statement below always,sometimes,or never true? Give at least two examples to support your reasoning. The LCM of two numb
Natali5045456 [20]

Answer:

  • True for Co-Prime Numbers
  • False for Non Co-Prime Numbers

Step-by-step explanation:

<u>STATEMENT:</u> The LCM of two numbers is the product of the two numbers.

This statement is not true except if the two numbers are co-prime numbers.

Two integers a and b are said to be co-prime if the only positive integer  that divides both of them is 1.

<u>Example: </u>

  • Given the numbers 4 and 7, the only integer that divides them is 1, therefore they are co-prime numbers and their LCM is their product 28.
  • However, consider the number 4 and 8. 1,2 and 4 divides both numbers, they are not co-prime, Their LCM is 8 which is not the product of the numbers.
3 0
3 years ago
What is the ratio of x=8y
Lemur [1.5K]
Its going to be 8  y= x/8
6 0
3 years ago
Read 2 more answers
On Monday John bought 7 apples. On Tuesday he bought 3 times as many apples as he did on Monday. How many apples did John buy on
d1i1m1o1n [39]
He brought 21 apples.
8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id
taurus [48]

Answer:

\boxed{\bf \:  \cfrac{13}{5}}

<u>Or in Decimal:</u>

\boxed{\bf \: 2.6}

Step-by-step explanation:

<u>Given expression :-</u>

\sf \: ( 26 \div 100) \times 10

<u>Solution :-</u>

\sf  = (26 \div 100 )\times 10

This arithmetic expression may be rewritten as ;

\sf  =  \cfrac{26}{100}  \times 10

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

\sf  =  \cfrac{26}{10 \cancel0}  \times 1 \cancel0

<em>Results to;</em>

\sf  =  \:  \cfrac{26}{10}  \times 1

\sf  =  \:  \cfrac{26}{10}

Step 2: <u>Cancel 26 and 10</u><u> </u><u>by 2</u> :-

\sf  =  \cfrac{ \cancel{26}}{ \cancel{10}}

<em>Results to;</em>

\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }

\sf  =  \cfrac{13}{5}

<em>It can also be in Decimal.</em>

That is;

\sf = 2.6

Hence, the answer of the expression would be 13/5 or 2.6 .

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

3 0
3 years ago
Read 2 more answers
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