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3 years ago

What is z=77674844/085447

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

3 0

Answer:

909.041207??

Step-by-step explanation:

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This figure is 14 of a circle.

Wittaler [7]

Answer:

The perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.

Step-by-step explanation:

Given : A quarter of a circle with radius labeled 2 in.

Quarter of circle means fourth part of a circle (as shown in image by shaded part).

We have to find the perimeter of this shaded quarter of circle.

Perimeter is the sum of the dimension of the given figure.

Perimeter of circle is $2\pi r$

Since, we are given Quarter circle so its perimeter $\frac{2}{4} \pi r+r+r=\frac{1}{2} \pi r+r+r$

Perimeter of given figure = $\frac{1}{2} \pi r+r+r$

Perimeter of given figure = $\frac{1}{2}\cdot 3.14 \cdot 2+2+2=3.14+4=7.14$

Thus, the perimeter of a quarter of a circle with radius 2 inches is 7.1 inches.

6 0

3 years ago

Read 2 more answers

Suppose a Pony Express rider was paid $192 for 12 weeks of work. If he was paid the same amount each week,how much was he paid f

Masteriza [31]

$192 divided by 12 is 16 so 16 x 3 is 48. That is your answer $48. Your welcome bud.

5 0

3 years ago

What is the answer to the question

JulijaS [17]

The answer to the question is 13

6 0

3 years ago

Read 2 more answers

What is the correct value of x in the triangle

seraphim [82]

Answer: 4

Step-by-step explanation:

Using the 30°-60°-90° Triangle Theorem we know that the base side is half of the hypotenuse. That means it is half of 8 which is 4

4 0

3 years ago

Help!! Find missing value for each quadratic function

Svetllana [295]

I'll do the first one to get you started. The answer is -3

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Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

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Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

1 = a*0^2 + b*0 + c

1 = 0a + 0b + c

1 = c

c = 1

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Plug in (x,y) = (-1,0) and c = 1

y = ax^2 + bx + c

0 = a*(-1)^2 + b(-1) + 1

0 = 1a - 1b + 1

a-b+1 = 0

a-b = -1

a = b-1

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Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

0 = 2b

2b = 0

b = 0/2

b = 0

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If b = 0, then 'a' is...

a = b-1

a = 0-1

a = -1

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In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

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The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

y = -3

3 0

3 years ago