2100/1 or 4200/2, could be either
If the call cost 35 cents to use the card that leaves $12 that was from minutes. There is 4 quarters in a dollar, 12x4 is 48.
VERIFY:
$1=4
$2=8
$3=12
$4=16
$5=20
$6=24
$7=28
$8=32
$9=36
$10=40
$11=44
$12=48
Step-by-step explanation:

Collect like terms and simplify
[tex] -10n+30n=-36-24 \\ 20n = -60 [/tex]
Divide both sides of the equation by 20
[tex] 20n/20 = -60/20 \\ n=-3 [/tex]
Answer:
A: the proposed route is 3.09 miles, so exceeds the city's limit
Step-by-step explanation:
The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...
a^2 = (12-6)^2 +3^2 = 45
a = √45 = 3√5
and
b^2 = (6 -2)^2 +4^2 = 32
b = √32 = 4√2
Then the total length, in grid squares, is ...
3√5 + 4√2 = 6.7082 +5.6569 = 12.3651
If each grid square is 1/4 mile, then 12.3651 grid squares is about ...
(12.3651 squares) · (1/4 mile/square) = 3.0913 miles
The proposed route is too long by 0.09 miles.
Answer:
Step-by-step explanation:
<u>Use cosine:</u>
- cos = adjacent / hypotenuse
- cos ∠L = KL/JL
- cos 21° = 4/x
- x = 4 / cos 21°
- x = 4.3 (rounded)