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Svetlanka [38]
3 years ago
15

Cual es la mitad de 1.5

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

\dfrac{1.5}2=\dfrac{15}{20}=\dfrac{3}{4}=0.75.

Green eyes.

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Find the product of the given polynomials. <br> (5x + 8 – 6r) (4 + 2r – 7)<br><br><br>​
Inessa05 [86]

Answer:

-12r² + 10xr - 15x + 34r - 24

Step-by-step explanation:

1. Organize it, variables first - as well as adding constants such as 4 and -7

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2. Start by multiplying the 5x by (2r - 3), then -6r, followed by 8

(10xr - 15x) + (-12r^2 + 18r) + (16r - 24)

3. Simplify

10xr - 15x - 12r² + 18r + 16r - 24

4. Order by greatest to smallest factorial

-12r² + 10xr - 15x + 18r + 16r - 24

5. Combine like variables

-12r² + 10xr - 15x + 34r - 24

6 0
3 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
3 years ago
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