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dlinn [17]
3 years ago
7

How many planes appear in this figure? Name three points that are collinear. Are points a, b, c, and d coplanar? Explain. At wha

t does and ca interest db

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0
D, B, and A are collinear. Yes they are coplanar because they all lay on the same plane. And I don’t understand the last question
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What is the value of the expression below?
Ghella [55]

Answer:

A. 12

Step-by-step explanation:

use pemdas

4^4=16

20+8=28

28-16=12

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(\frac{2}{5})c

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Imagine a 8x8 chessboard, with king beginning from top left by how many routes can he reach bottom right
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How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
I NEED HELP THIS IS DUE IN 15 mins PLSSS SOMEBODY HELP ME!!!!!
Lera25 [3.4K]

Answer:

Standard \: form :\:y=  {x}^{2}  - 4x - 5\\Factored\: from:\:y = (x  + 1) (x - 5)

Step-by-step explanation:

y = (x - 2)^{2}  - 9 \\  y=  {x}^{2}   - 4x + 4 - 9 \\   \red{ \boxed{ \bold{y=  {x}^{2}  - 4x - 5}}} \\ is \: in \: standard \: form \\  \\ y = (x - 2)^{2}  - 9  \\ y =  (x - 2)^{2}  -  {3}^{2}  \\ y =  \{(x - 2) + 3\} \{(x - 2) - 3 \} \\ y = \{x - 2 + 3\} \{x - 2- 3 \} \\ \purple{ \boxed{ \bold{y = (x  + 1) (x - 5)}}} \\ is \: in \: factored \: form

8 0
3 years ago
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