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3 years ago

A triangle has side with the lengths 8x + 6, 5x -5 and -6x + 12. What is the perimeter of the triangle?

1 answer:

5 0

To find the perimeter you have to combine like terms. 8x + 5x - 6x is 7x and 6 - 5 + 12 is 13 so the perimeter of the triangle is 7x + 13

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Trigonometry: If f(x)= 2sinx + cosx using exact values find f (120 degrees). if possible show steps.

Arada [10]

Answer: f(120°) = (√3) + 1/2

Step-by-step explanation:

i will solve it with notable relations, because using a calculator is cutting steps.

f(120°) = 2*sin(120°) + cos(120°)

=2*sin(90° + 30°) + cos(90° + 30°)

here we can use the relations

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

sin(a + b) = cos(a)*sin(b) + cos(b)*sin(a)

then we have

f(120°) = 2*( cos(90°)*sin(30°) + cos(30°)*sin(90°)) + cos(90°)*cos(30°) - sin(90°)*sin(30°)

and

cos(90°) = 0

sin(90°) = 1

cos(30°) = (√3)/2

sin(30°) = 1/2

We replace those values in the equation and get:

f(120°) = 2*( 0 + (√3)/2) + 0 + 1/2 = (√3) + 1/2

3 0

3 years ago

Suppose there are eight different management trainee positions to be assigned to eight employees in a company’s junior managemen

Alina [70]

8 positions x 8 employees = 64 different ways

8 0

3 years ago

Please answer ASAP, thank you!

Mkey [24]

Answer:

1) a = 110

2) b = 65

3) c = 115 d= 65 e = 115

How I found the last one?

The whole thing equals 360.

d is equal to 65 so I added those together.

That equals 130. So i subtracted that from 360.

I got 230. Next, I divided that by 2 to get the final 2 angles.

4 0

3 years ago

Read 2 more answers

Graph the image of the given triangle after the transformation that has the rule (x, y)→(x−5, y+6)

alexandr1967 [171]

Here is the cords:

(-2,-7) = (-7,-1)

(-1,-4) = (-6,2)

(5,-6) = (0,0)

4 0

3 years ago

Read 2 more answers

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3>Correct Question :-</h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3>Given :- </h3>

We have AP, 

$\sf{ 2 , 14 ,.... 98 }$
AP is the arithmetic progression or a sequence of numbers in which succeeding number is differ from preceeding number by a common value.

<h3>Solution :-</h3>

We have an AP :- 2 , 14 .....98

Therefore,

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

Here,

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

Now, 

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago