The length of AA' is the squareroot of 29.
Answer:
y=-x-4
Step-by-step explanation:
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
The figure consists of a rectangle and a circle.
first lets find the sides of the triangle
sides of the triangle are 4+4=8 and 3+1=4
therefore area of the rectangle is 8*4=32
now area of semicircle =πr^2/2 = π2^2/2=2π=6.3
we have to add the area of rectangle with the area of semicircle
this is because it the given figure no part of area of circle and rectangle are in common.
therefore total area of given figure = 32+6.3=38.3
Answer:
15 cups
Step-by-step explanation:
5x3 is 15
even the denominator by multiplying.
do what you multiplied on the numerator.
