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Scorpion4ik [409]
3 years ago
7

Three ratios that are equivalent to 8:5

Mathematics
2 answers:
saul85 [17]3 years ago
5 0

Answer:

16:10, 4:2.5, 24:15

Step-by-step explanation:

i multiplied each value by 2 and 3 and on the second one i divided by 2

brainliest pls

Jlenok [28]3 years ago
5 0

Answer:

16 : 5

8√2 : 5√2

1 : 5/8

Step-by-step explanation:

Equivalent to 8:5 means that you apply the same multiplication factor to not the 8 and the 5. Do <em>not</em> just add or subtract the same number to 5 and 8, because it just doesn't work like that.

1. Applying factor 2 gives 8*2 : 5*2

16 : 5

2. Applying factor √2 gives

8*√2 : 5*√2

8√2 : 5√2

3. Applying factor 1/8 gives

8*1/8 : 5*1/8

8/8 : 5/8

1 : 5/8

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The diameter of a circular rug is 5.6 feet what is the circumference
Brut [27]

Answer:

10.12

Step-by-step explanation:

5.6x2

5 0
4 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
3 years ago
Please help me i’ll give extra points.
maksim [4K]

Answer:

6

Step-by-step explanation:

6 0
3 years ago
mr.lumen replaced a square window with a rectangular one.The new window is 3 ft wider and 2 ft higher than the square one.it has
stira [4]

Alright, lets get started.

Suppose the original square window has the side = x feet

The new window is 3 ft wider and 2 ft higher than the square one.

Means length of the new window will be = (x+3)

Width of the new window will be = (x+2)

So the area of the new window will be = (x+3)(x+2)

So the area of the new window will be = x^2 + 2x + 3x + 6

So the area of the new window will be = x^2 + 5x + 6

As given in question the area of 30 square feet for the new window, hence

x^2 + 5x + 6 = 30

x^2 + 5x - 24 = 0

Factoring

(x+8)(x-3) = 0

x = -8 or x = 3

Side could not be negative hence

side of the original square window will be = 3 feet : Answer

Hope it will help :)

6 0
4 years ago
Read 2 more answers
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