Answer:
(5,-1) or x=5 y=-1
Step-by-step explanation:
I used the substitution method to solve this!
<em>1. Pick one of your equations and solve for one of the variables. I chose the first equation and solved for x.</em>
x-2y=7
(Move the -2y to the other side of the equation in order to get the x by itself. You do the opposite, so it becomes +2y.)
x=2y+7
<em>2. Now take your second equation and plug in what you got for x into the x variable.</em>
2(2y+7)+5y=5
(Multiple 2 by everything inside of the parentheses.)
4y+14+5y=5
(We want to get the y by itself, so move the 14 to the other side.)
4y+5y=-14+5
(Combine all the like terms.)
9y=-9
(Divide the 9 from the y. What you do to one side you must do to the other.)
y=-1
<em>3. Since you have one variable solved for. Now take the first equation and plug in your y.</em>
x-2(-1)=7
(Multiple -2 by -1)
x+2=7
(Move the 2 to the other side in order to get the x by itself.)
x=5
<em>4. If needed, plug in your x and y values into the equations in order to check your answer.</em>
Hope this could help!
Answer:
$425.6 is the amount that needs to be budgeted
Step-by-step explanation:
P(Y >y)=0.1
3
P(
(Y − µ
)/σ > (y − 400
)/20 )=0.1
3
P(Z >( y − 400
)/20 )=0.1
3
(y − 400
)/20
≈ 1.28
y ≈ (1.28)(20) + 400
y ≈ 425.60
Answer:
Step-by-step explanation:
For a. you are asked to evaluate f(0). This is a piecewise function with different domains for each piece of the function. You can only evaluate f(0) in the function that has a domain that allows 0 in it. In the first domain, it says
x < -3. 0 is not less than -3, so 0 is not in that domain, so you will not use that "piece" of the function to evaluate f(0).
In the next domain, it says that x is greater than or equal to -3 and less than 0. Again, 0 is not included in that domain, so we can't use that "piece" of the function to evaluate f(0).
The last domain says that x is greater than OR EQUAL TO 0, so this is where we evaluate f(0):
f(0) = -0 - 4 so
f(0) = -4
When we want to evaluate f(2), we follow the same rules. Find the piece of the function that allows 2 in its domain. That's the middle piece:
f(2) = 2(2) - 6 so
f(2) = -2
Answer:
5 faces and 6 vertices
Step-by-step explanation:
