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3 years ago

15

What is the definition of an irrational number????

1 answer:

77julia77 [94]3 years ago

7 0

Answer:

the irrational numbers are all the real numbers which are not rational numbers.

Step-by-step explanation:

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Find the value of x, and measure of angle A. (2x+60) (5x+2) 40

LuckyWell [14K]

Answer:

Step-by-step explanation:

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3 years ago

Solve and model 7/10-3/10

sergij07 [2.7K]

Hello,

$\frac{7}{10} - \frac{3}{10}$ = 2/5

Solution.

<span> $\frac{7}{10} - \frac{3}{10}$ = The denominators are the same so you subtract the numerator. Your answer should be </span> $\frac{4}{10}$ simplified your answer is $\frac{2}{5}$ .

Have A Good Day!

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3 years ago

Simply. 12x - 4x + 22<br> The simplified expression is ___x + ____.

bezimeni [28]

Answer:

8x + 22

Step-by-step explanation:

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2 years ago

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Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

8 0

3 years ago

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Help help please!

defon

Answer:

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Step-by-step explanation:

4 0

3 years ago

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