What is the definition of an irrational number????
1 answer:
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Answer:
Initial amount;
2110.6
Common ratio;
0.0201
Equation;
Step-by-step explanation:
In this scenario, the month represents the independent variable x while the membership amount represents the dependent variable y.
The analysis is performed in Ms. Excel. The first step is to obtain a scatter plot of the data then finally inserting an exponential trend line to obtain the required equation.
The Ms. Excel output is shown in the attachment below. To obtain the initial amount we substitute x = 0 in the equation. On the other hand, the common ratio is the exponent in the equation.
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>
<span>
Part B:
The mean of a binomial distribution is given by
</span>
<span>
The standard deviation is given by:
</span>
<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>
<span>
Part B:
The mean of a binomial distribution is given by
</span>
<span>
The standard deviation is given by:
</span>
<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>