Write an equation in slope intercept form for the line that passes through (-6,-2) and has a slope of 1/3

Mathematics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

y=1/3x-2

Step-by-step explanation:

Since the slope intercept form formula is y=mx+b all we need to do is input the values. So m is the slope. Input 1/3. X is next to it because we solve for this. B is the y intercept. Meaning its the point that crosses the line on the graph that is vertical. And you already have -2. Since we know: (x,y) so choose the y. And you have your equation.

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To the nearest tenth, find the perimeter of ∆ABC with vertices A(-1,4), B(-2,1) and C(2,1).

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First we need to find the length of each side of the triangle , and for that we need to use the distance formula, that is
$d =\sqrt{(x_{2} -x_{1})^2 +(y_{2} -y_{1})^2}$
$AB = \sqrt{(1-4)^2 +(-2+1)^2}= \sqrt{10}$
$\sqrt{BC} = \sqrt{(1-1)^2 + (2+2)^2}=4$
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$Perimeter = AB + BC + AC = \sqrt{10}+4 +\sqrt{18}$
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