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sp2606 [1]
3 years ago
12

F(x) = 3x-1 and g(x)=2x^2

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

a.  here you are to multiply the two functions together:

(3x-1)(2x^{2} )=6x^{3}-2x^{2}

b.  here you are to subtract g from f:

(3x-1)-(2x^{2})=-2x^{2}+3x-1

c.  here you are to compose g into f.  In other words, pick up the whole g function and plug it into f wherever you see an x:

3(2x^{2} )-1=6x^{2} -1

d.  here you are compose f into g.  In other words, pick up the whole f function and plug it into g wherever you see an x:

2(3x-1)^2

You now have to FOIL out the (3x-1) like so:

2[(3x-1)(3x-1)]

which gives you

2(9x^{2} -6x+1)

Distribute in the 2 and you'll end up with the answer:

18x^{2} -12x+2

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What is the missing numerator? blank over five plus eighteen over twenty equals thirty over twenty 8 5 3 2
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To find:

The missing value.

Solution:

Let x be the missing value.

We have,

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3 years ago
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