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iVinArrow [24]
2 years ago
12

Question 5 of 5

Mathematics
1 answer:
Ksju [112]2 years ago
8 0
Rotation about the origin
You might be interested in
The germination rate is the rate at which plants begin to grow after the seed is planted.
chubhunter [2.5K]

Answer:

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

\hat p=\frac{7}{15}=0.467 estimated proportion of seeds germinated

p_o=0.9 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0
3 years ago
A group of friends goes out to lunch and decides to split the bill. Their bill is $32.50, plus they want to leave a 20% tip. The
Ilya [14]

Answer:

9.75

Step-by-step explanation:

6.5= 20% of 32.50

32.50+6.5= 39

39/4 = 9.75

5 0
2 years ago
SImplify: ((x+3)/9)/((x+12/)6)
dexar [7]
Flip the bottom part after the "/" so you get ((x+3)/9)*(6/(x+12)) Cancel and multiply to get 2(x+3)/3(x+12) this is as simplified as it is going to get.
5 0
3 years ago
At 4:00 am the outside temperature was 28*F. By 4:00 pm that same day it rose to 38 degrees.
BigorU [14]
The temperature is 66*F.
6 0
3 years ago
CAN SOMEONE PLZZ HELP ME THE LAST QUESTION PLZZZZZ?????
MissTica

first is proportional. y is 1 and 1/4 times x

second is not proportional.

reason? divided any y value by its corresponding x value and you'll keep getting 1.25, or 1 and 1/4. and the second one is not proportional because dividing the y values by their corresponding x value will give different answers.

maybe im wrong maybe im right you choose to trust me or not.

5 0
3 years ago
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