Answer:
-6
Step-by-step explanation:
The slope of a line is given with the formula
Using the first two points, (-2, 8) and (-1, 2), we have
m = (2-8)/(-1--2) = -6/(-1+2) = -6/1 = -6
F(x) = -3x + 7
y = -3x + 7
x = -3y + 7
-3y + 7 = x
-3y = x - 7
y = -1/3x + 7/3
f^-1(x) = -1/3x + 7/3
Answer:
3872/(x^2 - 2)
Step-by-step explanation:
Simplify the following:
(16^3 - 3^2 - 5×43)/(x^2 - 2)
3^2 = 9:
(16^3 - 9 - 5×43)/(x^2 - 2)
16^3 = 16×16^2:
(16×16^2 - 9 - 5×43)/(x^2 - 2)
| 1 | 6
× | 1 | 6
| 9 | 6
1 | 6 | 0
2 | 5 | 6:
(16×256 - 9 - 5×43)/(x^2 - 2)
16×256 = 4096:
(4096 - 9 - 5×43)/(x^2 - 2)
43 (-5) = -215:
(4096 - 9 + -215)/(x^2 - 2)
4096 - 9 - 215 = 3872:
Answer: 3872/(x^2 - 2)
Answer:
mmm, well, not much we can do per se, you'd need to use a calculator.
I'd like to point out you'd need a calculator that has regression features, namely something like a TI83 or TI83+ or higher.
That said, you can find online calculators with "quadratic regression" features, which is what this, all you do is enter the value pairs in it, to get the equation.
Step-by-step explanation:
The data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9
<h3>When a measure is considered an outlier in a data-set?</h3>
A measure is considered an outlier in a data-set if it is very far from other measures, especially in these two cases:
- If the measure is considerably less than the second smallest value.
- If the measure is considerably more than the second highest value.
In this problem, he data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9.
The second highest value is 5.3, which is considerably less than 22.6, hence 22.6 is an outlier in the data-set.
More can be learned about statistical outliers at brainly.com/question/9264641
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