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2 years ago

Is -3x^5y^2+4x^3y+10x^2 written in standard form?

1 answer:

Alex2 years ago

4 0

I think so but it’s kind of hard to tell.

The answer should be: Yes because the terms are all written in the order of highest degree to the lowest degree.

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Find the midpoint of the line segment joining the points (-2,-2) and (-4,9).

11Alexandr11 [23.1K]

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-2,-2) and (-4,9).

The midpoint is

$M = ( \frac{ - 2 - 4}{2} \: , \: \frac{ - 2 + 9}{2} ) \\ = ( - \frac{6}{2} \: , \: \frac{7}{2} )$

We have the final answer as

$( - 3 \: , \: \frac{7}{2} )$

Hope this helps you

4 0

2 years ago

Using PEMDAS solve<br> 22/2x3

emmainna [20.7K]

22/2 = 11
11 x 3 = 33

7 0

3 years ago

Read 2 more answers

FaSSSSSSTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT and thanks yall are fast

Mama L [17]

Answer:

120 degrees

Step-by-step explanation:

It's a vertical angle, meaning that it is congruent to the one on the opposite side of it.

5 0

2 years ago

1. LeAnn has 20 coins in her piggy bank. All the coins are either pennies or dimes. The total value of the coins is 83 cents. H

mafiozo [28]

There is 7 dimes and 13 pennies

8 0

2 years ago

In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales

mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The sample size and the estimate are given by:

$n = 161, \pi = \frac{37}{161} = 0.2298$

Hence:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948$

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

5 0

2 years ago