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1 year ago

PLSS HELP ME WITH THIS !! 20 POINTSS

Mathematics

2 answers:

OLEGan [10]1 year ago

5 0

Answer:

Constant of Proportionality is k = y/x

Step-by-step explanation:

k = 0.5/1 = 0.5

vredina [299]1 year ago

3 0

Answer:

k = 0.5

Step-by-step explanation:

the constant of proportionality is the slope of the line

using the point (1, 0.5 ) , then

k = $\frac{y}{x}$ = $\frac{0.5}{1}$ = 0.5

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Evaluate the expression 2 x (3 + 1) + 2.

nekit [7.7K]

Answer:8x+2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

When a fraction of 12 is taken away from 17, what remain exceed one-third of seventeen by six.

vova2212 [387]

X - the fraction

$17- 12x=\frac{1}{3} \times 17+6 \\
17-12x=\frac{17}{3}+6 \\
-12x=\frac{17}{3}+6-17 \\
-12x=\frac{17}{3}-11 \\
-12x=\frac{17}{3}-\frac{33}{3} \\
-12x=-\frac{16}{3} \\
x=-\frac{16}{3} \times (-\frac{1}{12}) \\
x=\frac{16}{36} \\
x=\frac{4}{9}$

The fraction is 4/9.

5 0

2 years ago

A rectangles tabletop has a length of 4 3/4 feet and a area of 11 7/8 square feet what is the width of the tabletop

Natalija [7]

Area is length times width. Therefore, width is area divided by length. Convert 11 7/8 to the improper fraction 95/8 and convert 4 3/4 to 19/4. Then, you can fine 95/8 divided by 19/4 by flipping the second fraction and multiplying so that you have 95/8 times 4/19. 4 times 95 is 380 and 8 times 19 is 152. Therefore, the answer is 380/152. This is equivalent to 5/2 or 2.5.

3 0

2 years ago

Can you help me please

Setler [38]

I think this question is a part of another question; you can have any ratio that can add up to 114 cm.

5 0

3 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

2 years ago