Question

Based on the tree diagram below, what is the probability that a student doesn't have lice, given that the student tested negative? Round your answer to the nearest tenth of a percent.
A. 97.6%
B. 99.4%
C. 96.4%
D. 98.6%

Answer 1

Answer: D

Step-by-step explanation:

apec

Answer 2

Answer:

Option D (APEX)

Step-by-step explanation:

L= Student has lice

NL= Student has no lice

PT=Test Shows positive

NT=Test Shows negative

P($\frac{NT}{NL}$) =0.7708 (Probability that a student has no lice and the test shows negative)

P($\frac{NT}{L}$) = 0.0108 ( Probability that a student has lice and the test shows negative)

1. $P\frac{NT}{NL}$ = $\frac{P\frac{NT}{NL} }{P\frac{NT}{NL} +P\frac{NT}{L} }$
2. $\frac{0.7708}{0.7708+00108}$
3. $\frac{0.7708}{0.7816}$
4. 0.98618219 (Simplify)

Terms Of Percentages

0.98618219 × 100

=98.6

Therefore your answer is 98.6% (Option D)

APEX