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2 years ago

Solve the following equation Round to the nearest tenth 5.8 + 5.9x = 6x + 5

Mathematics

2 answers:

Jlenok [28]2 years ago

7 0

Answer:

x=8

Step-by-step explanation:

5.8+5.9x=6x+5

5.9x-6x=5-5.8

-0.1x= -0.8

x=8

Eduardwww [97]2 years ago

5 0

Answer:

x = 8

Step-by-step explanation:

1. Move the variables to be on one side of the equation. We will do this by canceling out 5.9x with -5.9. What you do to one side of the equation you must also do to the other.

5.8 + 5.9x = 6x + 5

-5.9x -5.9x

↓

5.8 = .1x + 5

2. Move the 5 to the left of the equation, so it can be with its like term. We will do this by canceling out 5 with -5. What you do to one side of the equation you must also do to the other.

5.8 = .1x + 5

-5 -5

↓

.8 = .1x

3. Get the x alone. Since x is being multiplied by .1 we will do this by dividing by .1. This is because division is the inverse of multiplication. What you do to one side of the equation you must also do to the other.

.8 = .1x

.1 .1

↓

8 = x

4. Rewrite the equation to have the variable come first.

x = 8

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Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

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2 years ago

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Allison and her children went into a bakery where they sell donuts for $2 each and cookies for $1 each. Allison has $20 to spend

KATRIN_1 [288]

Answer:

if donuts are 2 for each and cookies for 1 each it could be

X x 2 and X x 1

one equation could be 4 donuts for 2$ and 7 cookies for 1$

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2 years ago

A caterer has 5 rolls. He is ordering more rolls. He can order up to 9 packages of rolls and each package contains 12 rolls. The

stich3 [128]

B is the practical domain of the function

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3 years ago

Please help me!!!! You only have to answer number 1!!!

mrs_skeptik [129]

Given : A social media website has currently = 1,000 members.

In each month number of members gets triple.

To find: Equation that represents number of members m belongs to site.

Solution: Because we are given, each month the number of members gets triple, that means each month we can multiply by 3 to the number of members of previous month.

For first month, we would multiply 1,000 by 3.

For second month, we would multiply 1,000 by 3 *3.

For second month, we would multiply 1,000 by 3*3*3.

Each month one factor of 3 is being increasing.

We could write those 3's as exponents of 3.

Like $1000*3 = 1000*3^1$

$1000 * 3^2.$

$1000 * 3^3.$

As many months as many 3's are there.

So, the exponent of 3 is represnts the number of months.

Let us take a variable for number of month by n.

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2 years ago

In this diagram which equation could you prove to be true in order to conclude that the lines are parallel

KiRa [710]

I would say that the correct answer is D. because y is always the numerator while x is the denominator for the equation y2 - y1/x2 - x1 which means if there is two y's or two x's on the same line you subtract the second one from the first one. If there is only one y and/or x and the other is 0 on the same line, it stays at y or x without subtracting y2 - y1 or x2 - x1.

Since b is on the y coordinate and -a is on the x coordinate, you would make it b/a while -a is gonna be a positive since the lines are going up and to the right. Now, since c is the y coordinate and d is the x coordinate, make C the numerator and d the denominator since y is always the numerator and x is the denominator for these parallel line figures on the graph and the equation will be equaled to the fraction to the other fraction for parallel lines.

So, your answer would be D. b/a = c/d

Hope this helps, and is correct!

~ ShadowXReaper069

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3 years ago

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