1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vesnalui [34]
3 years ago
13

You have $700 to invest in an account and need to have $950 in one year. What interest rate would you need to have in order to r

each this goal if the amount is compounded quarterly? Round your answer to the nearest percent.
Please Help.
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

136% = 1.36

Step-by-step explanation:

(950-700)/700

=0.3571 (0.36)

Then you have to plus one

0.36+1

=136% or 1.36

You might be interested in
Please help. I’ll mark you as brainliest if correct!
Ivan

Answer:

A.

Step-by-step explanation:

5 0
4 years ago
Please Help me with this problem!!! ASAP
castortr0y [4]

The average rate of change is -5 per month

<h3>How to determine the average rate of change?</h3>

The interval is given as:

July to December

From the graph, we have:

July = 110

December = 30

The average rate of a function over the interval (a, b) is calculated as:

Rate = [f(b) - f(a)]/[b - a]

So, we have:

Rate = (30 - 110)/(December- July)

This gives

Rate = (30 - 110)/(12 - 7)

Evaluate

Rate = -16

Hence, the average rate of change is -5 per month

Read more about average rate of change at:

brainly.com/question/23715190

#SPJ1

6 0
2 years ago
(⚠️⚠️HELP!⚠️⚠️)Mary bought 18 books. Mary bought 6 times as many books as Carlos. Let b be the number of books that Carlos bough
kvasek [131]

Answer:

18=6b, b=3

Because Mary has 6 times as much as Carlos does, we put the x with 6. 18 is the number that 6x equals. 6*3=18

8 0
3 years ago
Read 2 more answers
A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func
djyliett [7]

Answer:

y=120 * 1.1^x --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

x \to months

y \to mice

So, we have:

(x_1,y_1) = (0,120) --- Monday

(x_2,y_2) = (1,132) --- One month later

Required

The function

The function is represented as:

y=ab^x

In (x_1,y_1) = (0,120), we have:

120 = a * b^0

120 = a * 1

120 = a

a=120

In (x_2,y_2) = (1,132), we have:

132 = a * b^1

132 = a * b

Substitute: a=120

132 = 120 * b

Solve for b

b = \frac{132}{120}

b = 1.1

So, the function is:

y=ab^x

y=120 * 1.1^x

To calculate the monthly rate (r), we have:

y =a(1 + r)^x

Compare to: y =ab^x

1 + r = b

Make r the subject

r = b-1

Substitute b = 1.1

r = 1.1-1

r = 0.1

Express as percentage

r = 0.1*100\%

r = 10\%

5 0
3 years ago
How do you do this??????
slava [35]

Answer:

2:1

Step-by-step explanation:

There are 14 spoons (not sure what they are) and 7 eyes so it is 14:7

simplified it is 2:1

Hope this helps :)

4 0
3 years ago
Read 2 more answers
Other questions:
  • It says one pound of horse hair is divided into pulls to make horse hair belts. One pull weighs about 0.011 ounces. How many pul
    11·2 answers
  • Graph. y-2=2/3(x+4).
    13·1 answer
  • Ax+3y=5 fine the missing coefficient (A) and also the completed equation
    11·1 answer
  • When you multiply a number by 4 and then subtract 7, the result is the same as if you first subtract 7 from the same number and
    8·1 answer
  • Find the range of the function for the given domain. F(x)= 3x-8; {-2, -1, 0, 1, 2}
    8·1 answer
  • 7676fhfghfhfghfhfhfh6
    6·1 answer
  • If a gradient of line a is 4 what is the gradient of the line perpendicular to a
    13·1 answer
  • I need you guy’s help answer thanks so much
    5·1 answer
  • A number line is shown below. 6 1/5 Which point is located at ? I will mark brainliest
    8·1 answer
  • This equation shows how the number of flowers Ed can have in his garden is related to the number of seed packets he purchases.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!