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pantera1 [17]
3 years ago
12

Estimate the square root of 60 to the nearest whole number

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0
Well the square root of 60 is 7.745966692 so 8 would be the absolute closest you can get

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Show me da way to the answer. Find the endpoint of the line segment with the given endpoint and midpoint.
soldi70 [24.7K]
(6, 9) is the other end point. This is because the given endpoint is 7 units below the midpoint. Therefore, the other one is seven above, at a y value of 9.
4 0
3 years ago
Find the perimeter of a square with sides that measure (2/3)g centimeters.
BARSIC [14]

Answer:

Perimeter of a SQUARE

4 x s

4 x 2.3 = 9.2 cm

Hence the perimeter of the square is 9.2cm

3 0
3 years ago
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Exponential function f is represented by the table. x -1 0 1 2 3 4 f(x) 7.5 7 6 4 0 -8 Function g is an exponential function pas
asambeis [7]

Answer:

A. Both functions are positive and decreasing on the interval.

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The table shows that f(x) decreases when x increases in the interval (0,3).

All the values of f(x) are positive in the interval (0,3).

For the exponential function that passes through the points (0, 27) and (3, 0), we also see that f(x) is decreasing when x increases: when x goes from 0 to 3, f(x) goes from 27 to 0.

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7 0
3 years ago
6000 for 6 years at 81/2 % compounded daily will grow to a) $9.990.02 b)9.060.00 c) 9788.81 d)9991.15
Flura [38]

Answer:

d)9991.15

Step-by-step explanation:

We have a sum of money ($6000) compounded daily at an annual interest rate of 8.5% for 6 years.

If the interest is compound daily, and we take a m=365 days a year (or 365 subperiods m), the daily nominal interest rate is:

i_d=\dfrac{i}{m}=\dfrac{0.085}{365}=0.000232877

Then, we can express the final valueo of $6000 compounded daily at an annual interest rate of 8.5% for 6 years as:

FV=IV\left(1+\dfrac{i}{m}\right)^{n\cdot m}\\\\\\FV=6000(1+0.000232877)^{6\cdot 365}\\\\FV=6000(1.000232877)^{2190}\\\\FV=6000\cdot1.665192322\\\\FV\approx9991.15

4 0
3 years ago
Help me please on math
V125BC [204]
What do you need help with
6 0
4 years ago
Read 2 more answers
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