Help me please on math

Suppose you work at a retail store that sells teddy bears. You always work 40 hours a week. The amount of your weekly paycheck i

brilliants [131]

a. Remember that f(x) is the amount of money you earned each week. Also note that teddybears = x

f(x) = 5x + 300 is your equation

5x + 300 is your expression

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b. A reasonable domain can be 0 < x < 50, in which x is the amount you sell. 50 is a bit far out, but it takes into account holidays, as well as places you may sell at that have large amount of people.

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c. f(20) means that you sold 20 teddy bears, as 20 replaces x, which (like what was stated above) is the amount you sell

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d. Plug in 25 for x.

5x + 300 = t (total amount you make)

5(25) + 300 = t

Remember to follow PEMDAS. First, multiply 5 with 25

5 x 25 = 125

Next, add

125 + 300 = t

t = 425

$425 is the amount you make in a week.

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e. Note that you make $425 if you sell 25 teddy bears. Also remember that you are paid a flat $300. Remember the formula:

f(x) = 5x + 300

Plug in 425 for f(x)

425 = 5x + 300

Isolate the x. Do the opposite of PEMDAS. Note the equal sign. What you do to one side, you do to the other.

First, subtract 300 from both sides

425 (-300) = 5x + 300 (-300)

425 - 300 = 5x

125 = 5x

Next, divide 5 from both sides

(125)/5 = (5x)/5

x = 125/5

x = 25

25 teddy bears must be sold

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hope this helps

4 0

3 years ago

Is (1,1) a solution the equation 2x - y = 1 ?

stealth61 [152]

Answer:

Yes

Step-by-step explanation:

2 times 1= 2

y=1

2-1=1

Yes

8 0

2 years ago

Read 2 more answers

Ling is 1 year less than twice as old as his sister. If the sum of their ages is 14 years how old is Ling

SashulF [63]

Sister is 5 
Yan Ling is 9 
9+5=14 
1 less than twice 5 is 9.

7 0

2 years ago

Round 452 to the nearest hundred

Anna007 [38]

Answer:

500

Step-by-step explanation:

6 0

3 years ago

Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin

Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

$ax^2+bx+c=0, a\neq 0$

Then to resolve a quadratic equation we apply Bhaskara's formula:

$x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}$

It usually has two solutions.

But it could happen that $\sqrt{b^2-4ac}$ then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0

3 years ago