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2 years ago

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The first rule is to add 10, then divide by 2 starting from 2. The second rule is to multiply by 3, then subtract 2 starting fro

m 2. What are the first four ordered pairs using the two sequences?

1 answer:

julsineya [31]2 years ago

5 0

Answer: $(2, 2), (6, 4), (8, 10), (9, 28)$

Step-by-step explanation:

The first four ordered pairs using the two sequences are: $(2, 2), (6, 4), (8, 10), (9, 28)$

The first rule is to add 10, then divide by 2 starting from 2

Add/Divide:

$10=2+10=12$

$2=12$ ÷ $2=6$

Add/divide again:

$10=6+10=16$

$2 = 20$ ÷ $2 = 10$ $2=16$ ÷ $2=8$

Add/divide again:

$10=8+10=18$

$2=18$ ÷ $2=9$

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*Missing Part of the Question*

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