Question

The first rule is to add 10, then divide by 2 starting from 2. The second rule is to multiply by 3, then subtract 2 starting from 2. What are the first four ordered pairs using the two sequences?

Answer 1

Answer: $(2, 2), (6, 4), (8, 10), (9, 28)$

Step-by-step explanation:

The first four ordered pairs using the two sequences are:$(2, 2), (6, 4), (8, 10), (9, 28)$

The first rule is to add 10, then divide by 2 starting from 2

Add/Divide:

$10=2+10=12$

$2=12$÷$2=6$

Add/divide again:

$10=6+10=16$

$2 = 20$÷$2 = 10$ $2=16$÷$2=8$

Add/divide again:

$10=8+10=18$

$2=18$÷$2=9$