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2 years ago

Please help me with this.

Mathematics

2 answers:

lesya [120]2 years ago

8 0

Answer:

v=8

Step-by-step explanation:

12=12+v−8/2

12=12+1/2

v+−4(Distribute)

12=(1/2v)+(12+−4)(Combine Like Terms)

12=1/2v+8

Step 2: Flip the equation.

1/2v+8=12

Step 3: Subtract 8 from both sides.

1/2v+8−8=12−8

Step 4: Multiply both sides by 2.

2*(1/2v)=(2)*(4)

v=8

lapo4ka [179]2 years ago

3 0

12 = 12 + (v - 8)/2
Subtract 12 from both sides
0 = (v - 8)/2
Multiple both sides by 2
0 = v - 8
Add 8 to both sides
8 = v
Therefore A is correct

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A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w

hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = $\pi r^2h$

$V=3.14\times (0.5 m)^2\times 5 =3.925 m^3$

Mass of gasoline = m

Density of gasoline = d = $673 kg/m^3$

$m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg$

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g $.8 m/s^2$

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

$W =m\times g\times h$

$W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J$

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

6 0

2 years ago

Someone please help!

Vlad1618 [11]

Multiply the top equation by 6 and the bottom equation by 7. You will cancel x first by doing this and solve for y. You should get y=-1.
Substitute in y for either original equation.
You should get x=1.
Solution is (1,-1).

7 0

2 years ago

which translation vectors could have been used for the pair of figures? PLEASE HELP I NEED A GOOD GRADE

kolbaska11 [484]

That would be d or f answer.

5 0

2 years ago

Read 2 more answers

Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,

Zinaida [17]

Answer:

The line of reflection is at y = x+6.

Step-by-step explanation:

The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...

y = 1(x +4) +2

y = x + 6 . . . . . . . line of reflection

6 0

3 years ago

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

2 years ago