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Blababa [14]
2 years ago
6

If four tires can be changed in 3/4 of an hour gow long would it take to change 19 cars​

Mathematics
1 answer:
kobusy [5.1K]2 years ago
5 0

Answer:

14.25 hours

Step-by-step explanation:

Four tires = 3/4 of an hour

=> 1 car = 3/4 of an hour

=> 19 cars = ?

=> If 1 = 3/4

=> 19 = 3/4 x 19

=> 3/4 x 19

=> 57/4

=> 14.25 hours

So, it would take 14.25 hours for 19 car's tires to be changed.

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She had 0.125% of the paint left over

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3 years ago
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How many 1/3 inch cubes does it take to fill a box with width 2 213 inches, length 3 1/3
MAVERICK [17]

Answer:

560 cubes

Step-by-step explanation:

Is 2 213 supposed to read 2 1/3? First calculate the volume of the box

V_box = 8/3 * 10/3 * 7/3 = 560/27 cubic inches

Now calculate the volume of your 1/3 inch cube:

V_cube = 1/3 * 1/3 * 1/3 = 1/27 cubic inches

Now divide the V_box by V_cube:

Number of boxes = (560/27) / (1/27) = (560/27) * (27/1) = 560 cubes

8 0
3 years ago
Help! open the attachment below!
gregori [183]

Answer:

yes it is

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6 0
2 years ago
What is the recursive formula for this arithmetic sequence 6, -24, 96, -384
Artemon [7]

Answer:

Option A. a_{1} =6  a_{n}= a_{n-1}(-4)

Step-by-step explanation:

The given sequence in the question is 6,-24,96,-384.......n

and we have to give the recursive formula for this arithmetic sequence.

We can re write the sequence to make it more simpler

6,6(-4),(-24)(-4),(96)(-4).......n terms

Now we can say a_{1} = 6

and a_{n}= a_{n-1}(-4)

Therefore the recursive formula of the sequence is a_{1} = 6

a_{n}= a_{n-1}(-4)

7 0
3 years ago
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
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