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zlopas [31]
3 years ago
15

Jan spends part of her year as a member of a gym. She then finds a better deal at another gym, so she cancels her membership wit

h the first gym after x months and spends the rest of the year, y months, with the second gym. The membership to the first gym costs $60 per month, while the membership for the second gym costs $50 per month. If she ended up spending a total of $660 over the course of the year, how much time did she spend at each gym?
Mathematics
1 answer:
denis23 [38]3 years ago
3 0

Answer:the spent 6 months at the first gym and 6 months at the second gym.

Step-by-step explanation:

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24/35  and the difference between two fractional numbers with same or equal denominators 5/7 and 2/7.

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Sofia made a scale drawing of a house. The scale she used was 1 millimeter : 6 meters. If the actual length of the garage is 12
romanna [79]

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6 0
3 years ago
the numbers of girls in the choir is 4 times the number of boys in the choir .the total number of students is 60..how many girls
Inessa05 [86]
First, make up some variables to represent the number of Girls and Boys in the choir.  

B = number of boys
G = number of girls

You know that there are 4 times as many girls in the choir as boys.  Therefore, the equation you can write is:
\frac{B}{G} =  \frac{1}{4}

If you cross-multiply, then you get the simplified equation:
G = 4B

Intuitively this makes sense since if you multiplied the number of boys in the class by 4, that would be equal to the number of girls you have.

Now, we know that the total class size is 60. So girls plus boys equals 60:
G+B = 60

To solve the equation, replace the G in this equation with the replacement you found before, 4B.
G + B = 60 -->
4B + B = 60 -->
5B = 60 -->
B = 12

However, you are trying to find the number of girls, so plug the answer back into your equation.
G + B = 60 -->
G + 12 = 60 -->
G + 12 -12 = 60 - 12 -->
G = 48

The number of girls you have is 48.

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3 years ago
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bearhunter [10]

Answer:

24 or 29 more numbers

Step-by-step explanation:

6 0
3 years ago
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