All categories

3 years ago

Jessica hit a golf ball 150.75 yards. Kayla hit a golf ball 130.25 yards. How much farther did Jessica hit a golf ball?

Mathematics

2 answers:

timofeeve [1]3 years ago

8 0

Answer:

20.5

Step-by-step explanation:

150.75 - 130.25 because jessica hit it further

Lapatulllka [165]3 years ago

6 0

Answer:

Jessica hit the golf ball 20.50 yards farther than Kayla.

Step-by-step explanation:

150.75 - 130.25 = 20.50 yards

If this answer is correct, please make me Brainliest!

You might be interested in

How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap

Ivan

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal. For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

6 0

3 years ago

If you buy 18 pounds of coffee into 0.25 pounds of bags how many small bags of coffee can the worker make

Sedbober [7]

72 small bags of coffe that worker can make becuase 18 divided by 0.25

5 0

3 years ago

Study the diagram of circle C.

poizon [28]

I think 90• I’m sorry if it’s not right

7 0

3 years ago

Read 2 more answers

If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?

7nadin3 [17]

Answer:

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

Step-by-step explanation:

Compare $ax^2+bx+c$ to $3x^2+4x-2$ .

We have $a=3,b=4,c=-2$ .

The quadratic formula is for solving equations of the form $ax^2+bx+c=0$ and is $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ .

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate $b^2-4ac$

Part 2: Evaluate $-b$

Part 3: Evaluate $2a$

------Let's do these parts.

Part 1: $b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40$ .

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant. If it is positive, you have two real solutions. If it is negative, you have no real solutions (both of the solutions are complex). If it is 0, you have one real solution.

Part 2: $-b=-4$ since $b=4$ .