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Cloud [144]
3 years ago
6

INTRO TO ALGEBRA 9x squared + 5y

Mathematics
2 answers:
Andrei [34K]3 years ago
7 0

what do you have to find

Artyom0805 [142]3 years ago
5 0

Answer: 24.464536 + 5y

Step-by-step explanation:

⇒ 9x squared (2.718282) + 5y

⇒ = 24.464536 + 5y

* Hopefully this helps:) Mark me the brainliest:) !!!

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Determine the quotient:2 4/7 ÷1 3/6
Lisa [10]
12/7. You put the numbers into mixed numbers giving you 18/7 and 9/6. For division you flip the second fraction and multiply them together. So you do 18/7 x 6/9. You're also able to cross cancel 18 and 9 giving you 2/7 x 6/1. 6 x 2 is 12 and 7 x 1 is 7. Your answer is 12/7.
3 0
3 years ago
Elena bought 8 tokens for $4.40. At this rate how many tokens could she buy with $6.05
maks197457 [2]

Answer:

She can buy 11 tokens

Step-by-step explanation:

8/4.40=x/6.05  (i set this up as a proportion. tokens/price=tokens/price)

4.40x=48.8  (cross multiplied)

x= 11  (divided both sides by 4.40)

7 0
3 years ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
3 years ago
You can afford a $1150 per month mortgage payment. You've found a 30 year loan at 8: interest compounded monthly. a) How big of
jarptica [38.1K]

Answer:

PV= Max Loan amount = PMT*B(i,T) and PMT = 1200. Calculate B(i,T) = B(6%/12, 360)

=(12/.06)(1-(1/(1.005))360)  I will let you complete the calculation

Step-by-step explanation:

3 0
2 years ago
Why y'all put 1\3 bdhchgf d gchg hello. helo0o elhwl
nydimaria [60]

Answer:

1/3=33.33%?

Step-by-step explanation:

the only math I see is 1/3 and a random 0 near O's

5 0
2 years ago
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