Question

a campground owner had 150 meters of fencing to enclose a rectangualr field adjacent to a river and also bisect that field into two equal halves. No fencing required with river. what are the dimesions of the largest area that can be enclosed

Answer 1

Answer:

Dimension of the Rectangle : 2W - 150 by W

Step-by-step explanation:

Given

Land Size = 150 metres

This land size represents the perimeter of the land

Let P = Perimeter

So, P = 150 m

To bisect the field into two equal halves means to divide length or width of the field into two equal halves

Let L = Length of the field

Let W = Width of the field

Assuming the length of the field is to be bisected., then the campground owner is left with 0.5L (i,e half of the length)

Perimeter of a rectangle is calculated by: 2(Length + Width)

P = 2(L + W) by substitution, becomes

150 = 2(0.5L + W) ----open bracket

150 = L + 2W ---- Male L the subject the formula

L = 2W - 150

The dimension of the largest area that can be enclosed id given by (L,W)

By substitution; the expression becomes

Dimension of the Rectangle : 2W - 150 by W