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DiKsa [7]
2 years ago
9

Please answer this question​

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
6 0

\bold{\huge{\underline{ Solution }}}

<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>

  • Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
  • Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>

  • A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

I have thought to make a 4 side polygon that is quadrilateral.

<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>

  • Step - 1 :- Draw a 5 cm line AB horizontally
  • Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
  • Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
  • Step - 4 :- Now, join the line AD
  • Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.

<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.

<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.

<h3><u>Now</u><u>, </u><u>we </u><u>have </u><u>to </u><u>find </u><u>the </u><u>sum </u><u>of </u><u>the</u><u> </u><u>angles</u><u> </u><u>of </u><u>the </u><u>polygon </u><u>:</u><u>-</u></h3>

<u>Here</u><u>, </u><u> </u>

  • All angles are equal in measure 90°

<u>Therefore</u><u>, </u>

The sum of the angles of the given polygon

\sf{ = 90{\degree} + 90{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 270{\degree} + 90{\degree} }

\sf{ = 360{\degree} }

Hence, The sum of the angles of the above polygon is 360° .

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eimsori [14]
I would go with D) incenter but im not too sure. 
x
7 0
3 years ago
Read 2 more answers
What’s the probability of getting each card out of a deck?
VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen​​​​​​​​​​​ is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

6 0
3 years ago
Find the value of x. (6x-3) 75°
Alenkinab [10]

the value of x is 13

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Peter drive 320 miles in 8 hours . calculate his average speed .
Ad libitum [116K]

Answer: 40

Step-by-step explanation:

You will take the miles he drove and divided it by the time it took him to get there

320/8=40

6 0
3 years ago
Read 2 more answers
Which model can be used to represent 0.111
weeeeeb [17]

Answer:

11.8845

Step-by-step explanation:

11.8845 to the up and down answer it will be down

4 0
3 years ago
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