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3 years ago

2 Points

Mathematics

1 answer:

alexdok [17]3 years ago

4 0

Answer:

Rx)=1/3x^2

Step-by-step explanation:

A horizontal stretch is simply making the parabola of the parent function wider, it's kind of like changing the slope of a line to make it less steep.

In the graph, the red line is the parent function and the blue line is the horizontally stretched function. See how the blue line appears to be stretched (horizontally).

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PLEASE HELP making Brainliest if correct

Oksana_A [137]

Can’t see the whole question, but they are congruent by ASA (if that is what they asked)

6 0

2 years ago

Which expression is equivalent to 4x2−(8x−4x2)+5+(4x−10)?

aivan3 [116]

As we look at the question Answer is :12x +15

4 0

2 years ago

Read 2 more answers

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Sever21 [200]

Answer:

-1

Step-by-step explanation:

Square both sides of the equation. (That is what is meant by "use the inverse relationship.")

$i^2=(\sqrt{-1})^2\\i^2=\boxed{-1} \qquad\text{simplify}$

8 0

3 years ago

A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

Taya2010 [7]

Answer:

The local maximum and minimum values are:

Local maximum

$g(0) = 0$

Local minima

$g(5.118) = -350.90$

$g(-1.368) = -9.90$

Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

$g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)$

Then, first and second derivatives of the function are, respectively:

First derivative

$g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)$

$g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}$

$g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x$

$g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)$

Second derivative

$g''(x) = 12\cdot x^{2}-30\cdot x -28$

Now, let equalize the first derivative to solve and solve the resulting equation:

$x\cdot (4\cdot x^{2}-15\cdot x -28) = 0$

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

$x\cdot (x-5.118)\cdot (x+1.368) = 0$

The critical points are 0, 5.118 and -1.368.

Each critical point is evaluated at the second derivative expression:

x = 0

$g''(0) = 12\cdot (0)^{2}-30\cdot (0) -28$

$g''(0) = -28$

This value leads to a local maximum.

x = 5.118

$g''(5.118) = 12\cdot (5.118)^{2}-30\cdot (5.118) -28$

$g''(5.118) = 132.787$

This value leads to a local minimum.

x = -1.368

$g''(-1.368) = 12\cdot (-1.368)^{2}-30\cdot (-1.368) -28$

$g''(-1.368) = 35.497$

This value leads to a local minimum.

Therefore, the local maximum and minimum values are:

Local maximum

$g(0) = (0)^{4}-5\cdot (0)^{3}-14\cdot (0)^{2}$

$g(0) = 0$

Local minima

$g(5.118) = (5.118)^{4}-5\cdot (5.118)^{3}-14\cdot (5.118)^{2}$

$g(5.118) = -350.90$

$g(-1.368) = (-1.368)^{4}-5\cdot (-1.368)^{3}-14\cdot (-1.368)^{2}$

$g(-1.368) = -9.90$

7 0

3 years ago

there were 936,795 bankruptcy filings in 2018. If there were 310,061 chapter 13 filings, what percent were not chapter 13

Marat540 [252]

66.90% of the total bankruptcy fillings are not chapter 13 fillings.

What is bankruptcy?

This is a situation where the management of a company declares that it could no longer pay its debt obligations as it does have the cash resources to do so.

In this case, the total number of bankruptcy fillings is 936,795, out of which 310,061 are chapter 13 filings

fillings that were not chapter 13=936,795-310,061

fillings that were not chapter 13=626,734

fillings that were not chapter 13 as % of total fillings=626,734/936,795

fillings that were not chapter 13 as % of total fillings=66.90%

Learn more on bankruptcy on:brainly.com/question/4418659

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4 0

2 years ago