We have by distributivity of limits over sums, and continuity of
and
, that

Given
, it follows that

Answer: -b - 9
Step-by-step explanation:
First, since the a cancel eachother out we are left with (4-b) + (-6-7)
Second, you want to add the -6 and -7 to get -13, so (4-b) - 13
Finally, add the 4 to the negative 13 to get (-b - 9)
Hope this helps.
You will need to set equations to solve for x and y coordinate.
(2+x)/2=4
2+x=8
x=6
(6+y)/2=10
6+y=20
y=14
The answer is A. (6,14)
Hi there!

We are given:
cos(7x)cos(4x) = -1 - sin(7x)sin(4x)
Begin by moving all terms with variables to one side:
cos(7x)cos(4x) + sin(7x)sin(4x) = -1
The corresponding trig identity is cos(A - B). Thus:
cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1
cos(3x) = -1
cos = -1 at π, so:
3x = π
x = π/3
We can also find another solution. Let 3π = -1:
3x = 3π
x = π
Thus, solutions on [0, 2π) are π/3 and π.