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3 years ago

Helppp meee !!!!!!!!!!!!!

Mathematics

1 answer:

Vitek1552 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

Since the denominator of each of those rational exponents is a 4, that means that the radical is a 4th root. The numerator of each exponent serves as the power on the given base. For example,

$2^{\frac{3}{5}}$ can be rewritten as

$\sqrt[5]{2^3}$

The little number that sits outside the radical, resting in the bend, is called the index. Our index is 4 (same as saying the 4th root). Put everything under the 4th root and let the numerator be the powers on each base:

$\sqrt[4]{6^1*b^3*c^1}$ which is written simpler as:

$\sqrt[4]{6b^3c}$

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A scuba diver descends in the water at a rate of 23 1/2

Makovka662 [10]

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.

Given:

A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.

A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.

To find :

The scuba diver's position relative to sea level after the 4.6 minutes.

Solution:

Rate of a scuba diver descending in the water for 2.6 minutes = $R _1$

$R_1= 23\frac{1}{2}ft/min=\frac{47}{2} ft/min$

Distance covered by a scuba diver in 2.6 minutes = $d_1$

$d_1=R_1\times 2.6min=\frac{47}{2} ft/min\times 2.6 min=61.1 ft$

Rate of a scuba diver ascending for 2 minutes = $R _2$

$R_2= 28ft/min$

Distance covered by a scuba diver in 2 minutes = $d_2$

$d_2=R_2\times 2min=28 ft/min\times 2 =56 ft$

The position of scuba diver after 4.6 minutes relative to sea level:

$d_1-d_2=61.1 ft-56 ft=5.1ft$

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.

Learn more about ascending rate and descending rate here:

brainly.com/question/1477877?referrer=searchResults

brainly.com/question/1072871?referrer=searchResults

3 0

3 years ago

In the triangle below, what is the measure of A?<br> ОА. 180°<br> Ос. 30°<br> ор. 90°

ICE Princess25 [194]

Answer:

60°

Step-by-step explanation:

Total angle measurement for a triangle is 180°

Equilateral triangle measures 60 on all angles. (60 + 60 + 60 = 180°)

This triangle is equilateral so it's angle is 60°.

Why is it equilateral? Because all sides of the triangle are equal (10 on all sides).

Hope this helps

3 0

3 years ago

Please answer this question! 30 points and brainliest!

tangare [24]

Answer:

3.5 cm

Step-by-step explanation:

2.5 is half of 5 so you divide 7 by 2 and you get 3.5

4 0

3 years ago

Read 2 more answers

Simplify the expression (128x^5/8x)^1/2

solong [7]

Answer: 4x'6

Step-by-step explanation:

Simplify x5 /8. Than, Equation at the end of step 1 : x5 ——) • x)1) ÷ 4 8

Step 2 : 2.1 16 = 24 (16)1 = (24)1 = 24 2.2 x6 raised to the 1 st power = x( 6 * 1 ) = x6

Step 3 : 24x6 Simplify ———— 4

Dividing exponents : 3.1 24 divided by 22 = 2(4 - 2) = 22

which brings us to our final answer above

5 0

3 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-3,1) and (2,-1) is $y=-\frac{2}{5}x-\frac{1}{5}$

8 0

3 years ago