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3 years ago

What is the gcf of 8,9,and10?

Mathematics

1 answer:

Elden [556K]3 years ago

6 0

The greatest common factor is 1 hope this helps you

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Name ____________________________________________Date_______ Class __ Score_______

Svetradugi [14.3K]

Answer:

its very long but ill help you with the first answer:18.5753424657534247

Step-by-step explanation:

7 0

3 years ago

Please show steps when solving this.

defon

$\frac{240 inches}{1 minute}$

We're going to change one unit at a time. Let's start with inches to feet. There are 12 inches in 1 foot. Divide 240 by 12 or multiply by 1/12.

$\frac{240 inches}{1 minute} * \frac{1 foot}{12 inches}=\frac{20 feet}{1 minute}$

Next, let's do the time using the same idea. Remember that there are 60 minutes in 1 hour.

$\frac{20 feet}{1 minute} * \frac{60 minutes}{1 hour} = \frac{1200feet}{1hour}$

Answer: 1200 feet per hour

Hope this helps!

7 0

2 years ago

The weight of an object on moon is 1/6 of its weight on Earth. If weight of an object on Earth is 18/5 kg, what would be its wei

IrinaVladis [17]

Answer:

3/5 kg

Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

<u>If it weights 18/5 kg on Earth then its weight on Moon is:</u>

18/5 * 1/6 = 3/5 kg

4 0

3 years ago

Read 2 more answers

I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it

anyanavicka [17]

Answer:

$\dfrac{16 y^{22}}{x^{10}z^{10}}$

Step-by-step explanation:

Given expression is ,

$\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}$

This would be simplified using the law of exponents , some of which I will use here are ,

$(an)^m = a^m n^m$
$\dfrac{a^m}{a^n}=a^{m-n}$

$a^m a^n = a^{m+n}$
$a^{-n} = \dfrac{1}{a^n}$

Using the above laws ,

$\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg) \bigg]^{-2}$

Using the second law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}$

Simplify ,

$\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}$

Using the first law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]$

Simplify,

$\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}$

Finally using the fourth law mentioned above , we have ,

$\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}$

<h3>Option K is the correct answer.</h3>

4 0

2 years ago

What is the area of the trapezoid shown below? 5 units 6 units 9 units

Helga [31]

Answer:

N/A

Step-by-step explanation:

Please be more specific, which is base and which is height

3 0

3 years ago