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mina [271]
3 years ago
7

7. A large population of ALOHA users manages to generate 60 requests/s, including originals and retransmissions. Time is slotted

in units of 50 ms. (Page 265 in the book may provide some help with this question.) (12 pts) a) What is the chance of success on the first attempt
Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

P(success at first attempt) = 0.1353

Step-by-step explanation:

This question follows poisson distribution. Thus, the formula is;

P(k) = (e^(-G) × (G)k)/k!

where;

G is number of frames generated in one frame transmission time(or frame slot time)

Let's find G.

To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.

Now, in 1000 ms, the number of frames generated = 50

Thus; number of frames generated in 50 ms is;

G = (50/1000) × 50

G = 2.5

To find the chance of success on the first attempt will be given by;

P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353

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Answer:

AY=8, XZ=20

Step-by-step explanation:

WY=WA+AY, plug in values: 14=6+AY, subtract 6 from both sides: 8=AY, AY=8cm

ZA=10cm and WY bisects XZ at A, so XA=ZA and XZ  = XA+ZA = 2ZA =2*10 = 20 cm

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I am a 4 digit number larger than 2,500. No two of my digits are the same. The product of the thousands digit and the hundreds d
gulaghasi [49]

Answer:

After 5 minutes of hitting my head on a wall I found your answer... 3256

Step-by-step explanation:

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3 years ago
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5 0
3 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
4 years ago
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