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Volgvan
2 years ago
10

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13 StartFraction 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma Sta

rtFraction 13 + StartRoot 153 EndRoot Over 2 EndFraction StartFraction negative 13 minus StartRoot 153 EndRoot Over 2 EndFraction comma StartFraction negative 13 + StartRoot 153 EndRoot Over 2 EndFraction
Mathematics
2 answers:
klasskru [66]2 years ago
5 0

Solution of the given expression  x^2 = -13x-4 is x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Step-by-step explanation:

We need to find solutions of x^2 = -13x-4

We need to solve the quadratic equation and find values of x.

Solving:

x^2 = -13x-4

Rearranging the terms:

x^2+13x+4=0

Solving the quadratic equation using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a = 1, b= 13 and c=4

putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(13)\pm\sqrt{(13)^2-4(1)(4)}}{2(1)}\\x=\frac{-13\pm\sqrt{169-16}}{2}\\x=\frac{-13\pm\sqrt{153}}{2}\\x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}

So, Solution of the given expression  x^2 = -13x-4 is x=\frac{-13+\sqrt{153}}{2}\,\,and\,\,x=\frac{-13-\sqrt{153}}{2}

Correct options are: Start Fraction negative 13 minus Start Root 153 End Root Over 2 End Fraction comma Start Fraction negative 13 + Start Root 153 End Root

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

  • brainly.com/question/4460262
  • brainly.com/question/7361044
  • brainly.com/question/1414350

#learnwithBrainly

Svetradugi [14.3K]2 years ago
3 0

Answer:

x_{1}=\frac{-13+\sqrt{153}}{2}\\x_{2}=\frac{-13-\sqrt{153}}{2}

Step-by-step explanation:

The given expression is

x^{2}=-13x-4

To solve this quadratic equation, we first need to place all terms in one side of the equation sign

x^{2} +13x+4=0

Now, to find all solutions of this expression, we have to use the quadratic formula

x_{1,2}=\frac{-b\±\sqrt{b^{2}-4ac}}{2a}

Where a=1, b=13 and c=4

Replacing these values in the formula, we have

x_{1,2}=\frac{-13\±\sqrt{(13)^{2}-4(1)(4)}}{2(1)}\\x_{1,2}=\frac{-13\±\sqrt{169-16}}{2}=\frac{-13\±\sqrt{153}}{2}

So, the solutions are

x_{1}=\frac{-13+\sqrt{153}}{2}\\x_{2}=\frac{-13-\sqrt{153}}{2}

If we approximate each solution, it would be

x_{1}=\frac{-13+\sqrt{153}}{2}\approx -0.32\\\\x_{2}=\frac{-13-\sqrt{153}}{2} \approx -12.68

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Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

2 {m}^{3}  - 12 {m}^{2}  + 18m

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Next you have to factorise the brackets :

{m}^{2}  - 6m + 9

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Explain why the graph below does not represent a direct variation. a. the line does not intercept the x-axis c. the line does no
Rama09 [41]

The graph is not a direct variation because the line does not go through the origin; option C.

<h3>What is a direct variation?</h3>

A direct variation is a relationship between two or more quantities in which as one quantity increases, the other quantity also increases. Similarly, if the other quantity decreases, the other decreases as well.

For the graph of a direct variation, the line must pass through the origin.

Therefore, the graph does not represent a direct variation because the line does not go through the origin.

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If the 7th of an AP is equal to 11 times the 11th term, find the 18th term
Zina [86]

Answer:

-33 or 33

Step-by-step explanation:

The seventh term of an AP is written as:

a + 6d

The eleventh term of an AP is written as:

a + 10d

If the 7th term is 11 times the 11th term, then;

a + 6d = 11(a + 10d)

Expand to get:

a + 6d = 11a + 110d

11a - a = 6d - 110d

10a =  - 104d

\frac{a}{d}  = -   \frac{104}{10}

\frac{a}{d}  = -   \frac{52}{5}

We must have a=-52 and d=5

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