THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Answer:
3)n×x^n-1
Step-by-step explanation:
Answer:
$50 each day
Step-by-step explanation:
240 - 90 = 150
150 / 3 = 50
<span> a∥e , m∥n , and m∠2 = 117°
<5 = 180 - <2
<5 = 180 - 117
<5 = 63
answer
</span><span>63°</span>
Seven tenths of every mile she goes she runs. So we would multiply 4 by seven tenths and get 2.8 miles. And to find out how many miles she walks, we would multiply 4 by three tenth and get 1.2
hope this helped!!
