I think the second one does
Answer:
Step-by-step explanation:
y = (x^2 + 4x) + 2
Take 1/2 of the linear term 4/2 = 2 and square that result. 2^2 = 4.
Put it after 4x
y = (x^2 + 4x + 4) +2 Subtract what you put inside the brackets on the outside.
y = (x^2 + 4x + 4) + 2 - 4 Combine the right.
y = (x^2 + 4x + 4) - 2 Express the brackets as a square.
y = (x + 2)^2 - 2
That's your answer
a = 1
h = 2
k = -2
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
I belive its number one :)
A numerical quality that is not a whole number.
