Please answer this correctly
2 answers:
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9514 1404 393
Answer:
- ∠QSR = 78°
- ∠SQR = 51°
Step-by-step explanation:
The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...
∠QSR = 2×∠QTR
∠QSR = 2×39°
∠QSR = 78°
__
Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...
∠QSR + 2(∠SQR) = 180°
78° + 2(∠SQR) = 180° . . . . fill in the value we know
2(∠SQR) = 102° . . . . . . . . . subtract 78°
∠SQR = 51° . . . . . . . . . . . . .divide by 2
Answer:
and
under this translation.
Step-by-step explanation:
A translation in is a mapping T from
to
defined by
, where
is a fixed vector in
.
From the problem we know that , so we need to find the values
and
such that
, so
and
, thus
and
.
Then and
Therefore and
. The triangles CAR and C'Q'R' are shown in the figure below.
